44+3x^2+60x=180

Solution for 44+3x^2+60x=180 equation:

44+3x^2+60x=180

We move all terms to the left:

44+3x^2+60x-(180)=0

We add all the numbers together, and all the variables

3x^2+60x-136=0

a = 3; b = 60; c = -136;
Δ = b2-4ac
Δ = 602-4·3·(-136)
Δ = 5232
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5232}=\sqrt{16*327}=\sqrt{16}*\sqrt{327}=4\sqrt{327}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-4\sqrt{327}}{2*3}=\frac{-60-4\sqrt{327}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+4\sqrt{327}}{2*3}=\frac{-60+4\sqrt{327}}{6}
$